How do you simplify (3n^-2)/(nm^-3)?

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How do you simplify (3n^-2)/(nm^-3)?

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Answer 1 · 2017-11-09T00:08:20

$\frac{3 m^{3}}{n^{3}}$ $(3m^3)/n^3$

Explanation:

$\frac{3 n^{- 2}}{n m^{- 3}}$ $(3n^-2)/(nm^-3)$
$= \frac{3 (\frac{1}{n^{2}})}{n (\frac{1}{m^{3}})}$ $=(3(1/n^2))/(n(1/m^3))$
$= \frac{\frac{3}{n^{2}}}{\frac{n}{m^{3}}}$ $=(3/n^2)/(n/m^3)$
$= (\frac{3}{n^{2}}) \cdot (\frac{m^{3}}{n})$ $=(3/n^2)*(m^3/n)$
$= \frac{3 m^{3}}{n^{3}}$ $=(3m^3)/n^3$

Further reading:
http://www.mathsisfun.com/algebra/negative-exponents.html

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How do you simplify (3n^-2)/(nm^-3)?

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