Question #2f265

1 Answer
Dwight
Nov 8, 2017

Not sure if you are saying that 2 and -6 are the roots, but if so, the equation is

#x^2+4x-12=0#

Explanation:

If 2 and -6 are the roots, then they must be the values of x that make the equation equal zero. This means we can write the factored form of the equation as

#(x-2)(x+6)=0#

(You can confirm that either #x=2# or #x=-6# would cause this to become zero.)

Now , use the FOIL method to multiply the binomials

#(x)(x) + (x)(6) + (x)(-2) + (-2)(6) = 0#

#x^2 +6x -2x-12=0#

#x^2+4x-12=0#

That is your equation. It includes #a=1#, #b=4# and #c=-12#

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