Question #3b038

Question

1204 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-11-07T20:37:02

12 sec

Consider this formula:

$D = v_{i} t + 0.5 a t^{2}$ $D = v_it + 0.5at^2$

The initial velocity $v_{i}$ $v_i$ is ZERO

Since the first term of the equation canceled,we can work out the time by using the second part.

$D = 0.5 a t^{2}$ $D = 0.5at^2$

$t^{2} = \frac{D}{0.5 a} = \frac{2 D}{a}$ $t^2 =D/(0.5a)=(2D)/a$

$t = \sqrt{\frac{2 D}{a}}$ $t =sqrt((2D)/a)$

plug in the numbers into the equation to get the answer.
$t=sqrt((2*245)/3.44)=11.93...$ (s).