Question #cd9fe

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Answer 1 · 2017-11-03T17:23:19

The molecular formula is #C_12H_10O_2#.

In this question, we have given a compound with molecular formula #C_(6x)H_(5x)O_x#. It can also be written as:

#xC_(6)H_(5)O#

where x is an empirical unit and #C_(6)H_(5)O# is an empirical formula.

Here, we can use an empirical unit formula to find the value of x.

#x=frac("molecular mass")("empirical mass")#

The empirical mass of #C_(6)H_(5)O# is given by:

#=6x12.01 "g/mol"+ 5x1.008 "g/mol"+ 1x16"g/mol" = 93.1 "g/mol"#

Now,

#x=frac("186 g/mol")("93.1 g/mol") = 1.997 \approx 2#

Therefore the molecular formula is: #C_(12)H_(10)O_2#.