Question #8c624

1 Answer
yumean1119
Nov 3, 2017

#1.05*10^-2# mol/L.

Explanation:

Fluoride ions containted in 1 L(=1000 g) of the solution is:
#1000 (g) * (200("ppm")) /(10^6) =0.200 (g)#.

The molar mass of fluorine atom is 19.00.
Thus, the molar concentration is
#(0.200(g/L))/(19.00(g/(mol)))=1.05*10^-2 ((mol)/L)#.

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