What is the equation of the line that passes through (3, 5) and (-7, -6)?

1 Answer
Manasvini Nittala
Oct 31, 2017

the equation of the line is #11x-10y+17=0#

Explanation:

the given two points are: #(x_1,y_1)=(3,5)#
#(x_2,y_2)=(-7,-6)#

the slope is #m=(y_2-y_1)/(x_2-x_1)=(-6-5)/(-7-1)=(-10)/-11=10/11#
the equation of a line passing through 2 points is
#(y-y_1)=(y_2-y_1)/(x_2-x_1)(x-x_1)#
#(y-5)=11/10(x-3)#
#10(y-5)=11(x-3)#
#11x-10y+17=0#

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