Question #a46f1

1 Answer
Oct 30, 2017

#"please look at the solution below."#

Explanation:

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  • The electric potential is a scalar quantity.
  • Electric charges are regularly distributed to the outer surface of the sphere.
  • When the solution is being made, it is assumed that the electric charge is collected at the center of the sphere.
  • Every point in the sphere has the same electric potential.
  • the electric potential of any point on the sphere is equal to the electric potential of any point within the sphere.
  • The electric potential of any point within sphere is maximum.
  • r is the radius of the sphere, d is the distance from the center of the sphere.
  • As you move away from the center of the globe, the electric potential decreases.

#" if d< r "=>V=k*(q)/(r)#

#" if d=r "=>V=k*(q)/r#

#" if d>r "=> V=k*(q)/(d)#

#"solution to the problem:"#

#q=20C#
#r=0.50m#
#k=9.10^9#

#"if d=0.50m :"#

#V=k*(20)/(0.50)=40k=40*9*10^9=360*10^9=3.6*10^(11) V.#

#"if d=0.80m :"#

#V=k*(20)/(0.80)=25k=25*9*10^9=225*10^(9)=2.25*10^(11)V.#