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Question #86887

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Oct 27, 2017

#2cos(2x)# or #2-4sin^2(x))#

Explanation:

#sin(2a)=2sin(a)cos(a)#
#cos(2a)=1-2sin^2(a)#

therefore:

#sin(4x)/sin(2x)=(2sin(2x)cos(2x))/sin(2x)=2cos(2x)#

#=2(1-2sin^2(x))=2-4sin^2(x))#

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