How do you evaluate #3.5/7 \times 3.06\div 3#?

1 Answer
Mia
Oct 24, 2017

#=0.51#

Explanation:

To perform an algebraic expression we should start with the
#" "#
strongest operation.
#" "#
The operation are organized in order starting with the strongest.
#" "#
Power
#" "#
#× ,÷# same strength
#" "#
#+,-# same strength
#" "#
In the given exercise , it is easier to perform
#" "#
#3.5/7=0.5" "# and #" "3.06÷3=1.02#
#" "#
#3.5/7 xx 3.06÷3#
#" "#
#=0.5 xx 1.02#
#" "#
#=0.510=0.51#

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