Question #241da

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Answer 1 · 2017-10-24T05:41:49

Let's rewrite it:

$= \frac{12}{3} \cdot (- 8 + {(- 4)}^{2} - 6) + 2$ $=12/3*(-8+(-4)^2-6)+2$

PEMDAS is a good "basic order of operations" acronym for:

PARENTHESES
EXPONENTS
MULTIPLICATION
DIVISION
ADDITION
SUBTRACTION

So, lets start with the power inside the parenthesis:
${(- 4)}^{2} = (- 4) (- 4) = 16$ $(-4)^2 = (-4)(-4) = 16$

$= \frac{12}{3} \cdot (- 8 + 16 - 6) + 2$ $=12/3*(-8+16-6)+2$

Then, inside the parenthesis:
$(- 8 + 16 - 6) = 2$ $(-8+16-6) = 2$

$= \frac{12}{3} \cdot 2 + 2$ $=12/3*2+2$

Then multiplication:
$\frac{12}{3} \cdot 2 = \frac{24}{3}$ $12/3*2 = 24/3$

$= \frac{24}{3} + 2$ $=24/3+2$

Now, addition:
$\frac{24}{3} + 2 = \frac{24}{3} + \frac{6}{3} = \frac{24 + 6}{3} = \frac{30}{3} = 10$ $24/3+2 = 24/3 + 6/3 = (24+6)/3 = 30/3 = 10$