Question #d48ce

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Question #d48ce

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Answer 1 · 2017-10-23T15:15:50

The coefficient of $x^5$ is $4032$

Explanation:

The expansion $(1+2x)^9$ is of the form $(1+X)^n$
The general term in the expansion $(1+X)^n$ is
$T_(r+1)=C_r(X)^n$
Here $X=2x and n=5$
on substituting we get
$(9!)/(4!.5!)(2x)^5$ $rArr126*32$ $x^5$
The coefficient of $x^5$ is $126*32=4032$
$:.$ coefficient of $(x)^5=4032$

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