How do you factor 48x ^ { 4} y ^ { 2} + 243y ^ { 2}?

1 Answer
Oct 21, 2017

3y^2(16x^4+81)

Explanation:

To factor the expression, we have to find the common factor first.
The common factor for 48 and 243 is 3

So, we know that common factor of 48x^4y^2 and 243y^2 is 3y^2.

Then, we can just take out the common factor as the following:

48x^4y^2 + 243y^2
=3y^2(16x^4+81)