How do you factor #48x ^ { 4} y ^ { 2} + 243y ^ { 2}#?

1 Answer
Yiu A.
Oct 21, 2017

#3y^2(16x^4+81)#

Explanation:

To factor the expression, we have to find the common factor first.
The common factor for #48 and 243# is #3#

So, we know that common factor of #48x^4y^2 and 243y^2# is #3y^2#.

Then, we can just take out the common factor as the following:

#48x^4y^2 + 243y^2#
#=3y^2(16x^4+81)#

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