How to divide $\frac{\sqrt{6}}{\sqrt{5} + \sqrt{2}}$ $sqrt6/(sqrt5+sqrt2$ ?

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Answer 1 · 2017-10-20T03:27:55

0.671

$\frac{\sqrt{6}}{\sqrt{5} + \sqrt{2}}$ $sqrt6/(sqrt5+sqrt2)$

Take the square root of each of the numbers in the equation which gives the following.

$\frac{2.449}{2.236 + 1.414}$ $2.449/(2.236+1.414)$

Adding the denominator gives:

$\frac{2.449}{3.650}$ $2.449/3.650$

$0.671$ $0.671$

How to divide √6√5+√2sqrt6/(sqrt5+sqrt2 ?