Question #eb60c

1 Answer
Bobert
Oct 18, 2017

#dy/dx=e^(3x-x^3)(3-3x^2)#

Explanation:

The derivative of #e^u#, where #u# is some function of #x#, is #dy/dx=e^u*(du)/dx#.

So, in this case, the derivative is:

#dy/dx=e^(3x-x^3)*d/dx(3x-x^3)#

Simplifying gives:

#dy/dx=e^(3x-x^3)(3-3x^2)#

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