What is the equation of the line that passes through (-6, -8) and (-7, y) and has a slope of -8?

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What is the equation of the line that passes through (-6, -8) and (-7, y) and has a slope of -8?

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Answer 1 · 2017-10-16T19:30:41

From here we just use the point (-6,-8) and slope -8 to write the equation.

Explanation:

The equation of line:
y=mx+c
we have y=-8 x=-6 and m=-8 , so we need to find c.
$- 8 = - 8 \cdot - 6 + c$ $-8=-8*-6+c$
$- 8 = 48 + c$ $-8=48+c$
$c = - 56$ $c=-56$
Equation is y=-8x-56

if you would like to know how to find y in point (-7,y) the solution is below, but you don't need it for this question.

The slope or gradient has this formula when two points are given:
$m = \frac{y 1 - y}{x 1 - x}$ $m=(y1-y)/(x1-x)$

In this case we have the points (-6,-8) and (-7,y) and m=-8.
We use the formula:

$- 8 = \frac{- 8 - y}{- 6 - (- 7)}$ $-8=(-8-y)/(-6-(-7))$
$- 8 = \frac{- 8 - y}{1}$ $-8=(-8-y)/1$
$- 8 + 8 = - y$ $-8+8=-y$

$y = 0$ $y=0$

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What is the equation of the line that passes through (-6, -8) and (-7, y) and has a slope of -8?

1 Answer

Explanation:

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