How do you solve #\frac { 8} { x } + \frac { 2} { x - 4} = \frac { x - 2} { x - 4}#?

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Answer 1 · 2017-10-16T05:23:23

#x=8#

#8/x+2/(x-4)=(x-2)/(x-4)#

#8/x=-2/(x-4)+(x-2)/(x-4)=(-2+x-2)/(x-4)=(x-4)/(x-4)=1#

#8/x=1#

#8/cancelx(cancelx)=1(x)#

#8=x#

To check, change all #x# to #8#:

#8/8+2/(8-4)=(8-2)/(8-4)#

#1+1/2=6/4#

#1 1/2=1 1/2#