How do you solve $\frac { p + 5} { p - 11} = \frac { 5} { 8}$ ?

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Answer 1 · 2017-10-15T07:03:52

$p=-31\frac{2}{3}$

$\frac{p+5}{p-11}=\frac{5}{8}$ , $p!=11$
$8(p+5)=5(p-11)$
$8p+40=5p-55$
$8p-5p=-55-40$
$3p=-95$
$p=-\frac{95}{3}=-31\frac{2}{3}$

How do you solve \frac { p + 5} { p - 11} = \frac { 5} { 8}\frac { p + 5} { p - 11} = \frac { 5} { 8}?