The center of gravity of a 50 g meter stick is at 51 cm and the stick is supported at 70 cm. Where must an 80 g object be hung in order to have equilibrium?

1 Answer
1s2s2p
Oct 14, 2017

#0.81875~~0.82m#

Explanation:

#\Sigma"Clockwise moments"=\Sigma"Anticlockwise moments"#

#\Sigma"Anticlockwise moments"=\SigmaFx=(0.05*9.81)(0.70-0.51)=(0.4905)(0.19)=0.093195Nm#

#\SigmaClockwise moments"=0.093195=\SigmaFx=(0.08*9.81)x#

#0.093195=0.7848x#

#x=0.093195/0.7848=0.11875~~0.12m#

However, we want the actual potion, which would be #x#m away from the pivot point, which is #0.70+0.11875=0.81875~~0.82m#

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