Question #f479f

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Question #f479f

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Answer 1 · 2017-10-12T22:34:38

0.61 moles of $O_{2}$ $O_2$ and 1.22 moles of $H_{2}$ $H_2$ O

Explanation:

After balancing the equation we discover that
$O_{2}$ $O_2$ + 2 $H_{2}$ $H_2$ $\to$ $rarr$ 2 $H_{2}$ $H_2$ O
in other words 1 mole of $O_{2}$ $O_2$ reacts with 2 moles of $H_{2}$ $H_2$ to produce 2 moles of $H_{2}$ $H_2$ O. The ratio of oxygen to hydrogen molecules in the reaction is a 1 : 2 ratio. So we must divide the moles of $H_{2}$ $H_2$ in half to determine the moles of $O_{2}$ $O_2$ . The ratio of $H_{2}$ $H_2$ to $H_{2}$ $H_2$ O is 2 : 2. This reduces to a 1 : 1 ratio, therefore the moles of $H_{2}$ $H_2$ is equal to the moles of $H_{2}$ $H_2$ O produced.

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