How do you solve $3 n - (4 n + 2) > 8$ $3n - ( 4n + 2) > 8$ ?

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Answer 1 · 2017-10-11T08:07:30

$3 n - (4 n + 2) > 8 = n < - 10$ $3n-(4n+2)>8=n<-10$

$3 n - (4 n + 2) > 8$ $3n-(4n+2)>8$

Remove the brackets first:

$3 n - 4 n - 2 > 8$ $3n-4n-2>8$

Move the n's to one side of the equation and the numbers to the other (change them from positive to negative or vice-versa when you do so):

$3 n - 4 n > 8 + 2$ $3n-4n>8+2$

$- n > 10$ $-n>10$

Don't forget to change the sign when you multiply by a negative number:

$n < - 10$ $n<-10$

How do you solve 3n−(4n+2)>83n - ( 4n + 2) > 8?