How do you solve $3n - ( 4n + 2) > 8$ ?

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Answer 1 · 2017-10-11T08:07:30

$3n-(4n+2)>8=n<-10$

$3n-(4n+2)>8$

Remove the brackets first:

$3n-4n-2>8$

Move the n's to one side of the equation and the numbers to the other (change them from positive to negative or vice-versa when you do so):

$3n-4n>8+2$

$-n>10$

Don't forget to change the sign when you multiply by a negative number:

$n<-10$

How do you solve 3n - ( 4n + 2) > 83n - ( 4n + 2) > 8?