How do you factor $7b + 4b ^ { 3}$ ?

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Answer 1 · 2017-10-09T02:15:34

The answer is $b(7+4b^2)$ .

Factor:

$7b + 4b^3$

Factor out the common $b$ .

$b(7+4b^2)$

Answer 2 · 2017-10-09T02:18:53

$=>b(b+7/4i)(b-7/4i)$

$(7b+4b^3)$
Taking out b
$=>b(7+4b^2)$
By the factorization of $(7+4b^2)$
$=>b(b+7/4i)(b-7/4i)$
Where $i$ is a imaginary number
$i^2=-1$

How do you factor 7b + 4b ^ { 3}7b + 4b ^ { 3}?