How do you solve -[ 4+ 2( x + 1) ] = 3( x + 1) + 3−[4+2(x+1)]=3(x+1)+3?

1 Answer
JoJoZ
Oct 7, 2017

-12/5=x−125=x

Explanation:

−[4+2(x+1)]=3(x+1)+3−[4+2(x+1)]=3(x+1)+3

Left side:

−[4 color(red)(+2(x+1) ]]=3(x+1)+3−[4+2(x+1)]=3(x+1)+3

−[4color(blue)(+2x+2)]=3(x+1)+3−[4+2x+2]=3(x+1)+3

−[color(red)4+2xcolor(red)(+2)]=3(x+1)+3−[4+2x+2]=3(x+1)+3

−[2x color(blue)(+6)]=3(x+1)+3−[2x+6]=3(x+1)+3

color(red)(−1[2x +6])=3(x+1)+3−1[2x+6]=3(x+1)+3

color(blue)(−2x -6)=3(x+1)+3−2x−6=3(x+1)+3

Right side:

−2x -6=3(x+1)+3−2x−6=3(x+1)+3

−2x -6=color(red)(3(x+1))+3−2x−6=3(x+1)+3

−2x -6=color(blue)(3x+3)+3−2x−6=3x+3+3

-2x -6=3xcolor(red)(+3+3)−2x−6=3x+3+3

-2x -6=3xcolor(blue)(+6)−2x−6=3x+6

Both Sides:

-2x(color(red)(-6-6))=3xcancel(color(red)(+6-6))

-2xcolor(blue)(-12)=3x

cancelcolor(red)(-2x+2x)-12=color(red)(3x+2x)

-12=color(blue)(5x)

color(red)(-12/5)=cancelcolor(red)(5/5)x

color(blue)(-12/5)=color(blue)x

-12/5=x

I hope this helps

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