The height from which the body is released is numerically equal to the velocity accquired find the that height is equal to ? Ans:2g

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Answer 1 · 2017-10-05T20:06:35

This is just algebra, but isn't simple...

Due to conservation of energy, # E_p# lost = #E_k# gained

So #m.g.h = 1/2mv^2#

So #g.h = 1/2v^2#

Or 2g.h = v^2

If we say v = h then substitute that into the previous equation,

#2g.h = h^2#

So dividing both sides by h get us

2g = h

That means if we drop an object of any mass from 19.82 m it will hit the ground at 19.82 m/s.