How do you solve $\frac{3 x + 6}{4} = \frac{2 x - 3}{5}$ $\frac { 3x + 6} { 4} = \frac { 2x - 3} { 5}$ ?

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Answer 1 · 2017-10-04T20:15:50

$x = - 6$ $x=-6$

To start, we want to get rid of the fractions to make it easier to work with.
So we can multiply the equation by 4 on each side.

$5 (\frac{3 x + 6}{4}) = 5 (\frac{2 x - 3}{5})$ $5((3x+6)/4)=5((2x-3)/5)$

$\frac{5 (3 x + 6)}{4} = 2 x - 3$ $(5(3x+6))/4=2x-3$

Now multiply by 4.

$4 (\frac{5 (3 x + 6)}{4}) = 4 (2 x - 3)$ $4((5(3x+6))/4)=4(2x-3)$

$5 (3 x + 6) = 4 (2 x - 3)$ $5(3x+6)=4(2x-3)$

Expand the brackets.

$15 x + 30 = 8 x - 12$ $15x+30=8x-12$

You can now bring all of the x's to one side and numbers to the other.

$7 x = - 42$ $7x=-42$

Divide through by 7 to leave x on its own.

$x = - 6$ $x=-6$

How do you solve \frac { 3x + 6} { 4} = \frac { 2x - 3} { 5}3x+64=2x−35\frac { 3x + 6} { 4} = \frac { 2x - 3} { 5}?