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A projectile is shot at an angle of #pi/6 # and a velocity of # 1 m/s#. How far away will the projectile land?

1 Answer

Oct 4, 2017

0.088 m

Explanation:

#"Initial Velocity"# #u=1 m/s#
#"Angle of Projection"# #theta=pi/6#

#"Horizontal Range"# #R=(u^2sin2theta)/g#
#R=(1^2sin(2pi/6))/9.8=sin(pi/3)/9.8=sqrt3/(2xx9.8)#
#R=0.088 m#

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