Question #eceda

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Answer 1 · 2017-10-03T18:47:31

The three numbers are #11, 12,# and #13# and their product is #1716#

The question suggests the following sum of three numbers:

#a+b+c=36#

and since we know they are consecutive, i.e. #b=a+1# and #c=a+2#, we can write:

#a+(a+1)+(a+2)=36#

#3a+3 = 36#

#3a = 33#

#a=11#

So the three numbers are #11, 12,# and #13#.

Finally the product is:

#11*12*13 = 1716#