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Answer 1 · 2017-10-02T16:08:50

The value of #x# comes to be 3.

Given that,
#log(x+2)-log(3x-4)=0#
#:.log(x+2)=log(3x-4)#

Now, taking antilog in both sides,

#x+2=3x-4#
#:.color(red)(x=3)#. (Answer).

Hope it Helps :)

Answer 2 · 2017-10-02T16:40:19

#x=3#

Assuming base #10# logarithms

#log(x+2) - log(3x-4)=0 => log(x+2)=log(3x-4)#

Raise #10# to the power of each side.

This is the antilogarithm, such that:

#10^log(a) = a#

So:

#10^log(x+2)= 10^log(3x-4)=> x+2=3x-4=> x=3#