How do you evaluate $\frac{6}{7} \cdot (\frac{11}{18} - \frac{5}{12})$ $\frac { 6} { 7} \cdot ( \frac { 11} { 18} - \frac { 5} { 12} )$ ?

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Answer 1 · 2017-09-28T18:26:59

$\frac{1}{6}$ $1/6$

find common denominators to make the subtraction easier

$\frac{6}{7} . (\frac{11}{18} - \frac{5}{12})$ $6/7 . (11/18 - 5/12)$

$\frac{6}{7} . (\frac{22}{36} - \frac{15}{36})$ $6/7 . (22/36 - 15/36)$

$\frac{6}{7} . \frac{7}{36}$ $6/7 . 7/36$

the 7's cancel each other out

$\frac{6}{36}$ $6/36$

$\frac{1}{6}$ $1/6$

How do you evaluate \frac { 6} { 7} \cdot ( \frac { 11} { 18} - \frac { 5} { 12} )67⋅(1118−512)\frac { 6} { 7} \cdot ( \frac { 11} { 18} - \frac { 5} { 12} )?