How do yo solve #6p - 3\leq 7+ p + 2+ 3p#?

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Answer 1 · 2017-09-28T05:57:15

#p<=6#

#6p-3<=7+p+2+3p#

Collecting like terms on the right side:

#6p-3<=4p+9#

Add #3# to both sides:

#6p-3+3<=4p+9+3#

#6p<=4p+12#

Subtract #4p# from both sides:

#6p-4p<=4p+12-4p#

#2p<=12#

Divide both sides by #2#:

#(2p)/2<=12/2#

#p<=6#