How do you solve #14+ 3|2x-5| = 17#?

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Answer 1 · 2017-09-26T10:13:45

Solution: # x=3 ,x=2#

#14 + 3 | 2x-5| =17 or 3 | 2x-5| =17-14 or 3 | 2x-5| =3 #

or #| 2x-5| =1 or 2x -5 =1 or 2x =6 or x=3 # OR

#14 + 3 | 2x-5| =17 or 3 | 2x-5| =17-14 or 3 | 2x-5| =3 #

or # | 2x-5| =1 or 2x -5 = -1 or 2x = 4 or x=2 #

Solution: # x=3 ,x=2# [Ans]

Answer 2 · 2017-09-26T10:20:15

#x = 2#
#x = 3#

First we would equal the equation to #0# be rearranging the equation.

#-3 + 3|2x−5| = 0#

Now for this equation to be complete, we know that #3|2x−5|# must equal to #3# for the equation to equal to #0#

#3|2x−5| = 3#

Therefore, dividing by 3 on both sides, we get

#|2x−5| = 1#

Since it is an absolute value we can have two equations

#2x−5 = -1#
#2x−5 = 1#

Rearranging to get #x# on its own, we solve for #x#

#x = (-1 + 5)/2#

#x = (1 + 5)/2#

#x = 2#
#x = 3#