Question #53cfd

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Question #53cfd

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Answer 1 · 2017-09-26T02:22:40

$x^{2} + y^{2} - 6 x - 10 y + 18 = 0$ $x^2+y^2-6x-10y+18=0$

Explanation:

Equation of a circle,given center coordinates and radius is
${(x - x_{1})}_{1}^{2} + {(y - y_{1})}_{1}^{2} = r^{2}$ $(x-x_1)^2 +(y-y_1)^2=r^2$
Here $x_{1}$ $x_1$ = 3 & $y_{1}$ $y_1$ = 5.
$:.$ Equation of the required circle is

$(x-3)^2+(y-5)^2=4^2$
$x^2-6x+9+y^2-10y+25=16$
$x^2+y^2-6x-10y+18=0$

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Question #53cfd

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