Question #1dd24

1 Answer
Fty
Sep 21, 2017

#6 xx 10^-5m#

Explanation:

To be able to find the wavelength we can use the wave equation. It is #c=flambda#
Where,
#c# is the speed of light = #3.00 xx 10^8m.s^-1#
#f# is frequency of the electromagnetic radiation
#lambda# is the wavelength

when rearranging this equation to solve for #lambda#, we get #lambda=c/f#.
#=(3.00 xx 10^8)/(5.00 xx 10^12)#
#= 6xx10^-5m#
For the second question we need to look at the electromagnetic radiation spectrum.
https://en.wikipedia.org/wiki/Electromagnetic_radiation
If you go back and have a look, both the wavelength and frequency correspond to the infra-red (IR).

Therefore, the answer is infra-red(IR).

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