Question #2c311

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Answer 1 · 2017-09-21T18:31:05

$2 > x > - 3$ $2 > x > -3$

Step one: subtract both sides by 1

$- 5 (- 1) < 1 - 3 x (- 1) < 10 (- 1)$ $-5color(red)((-1))< 1 - 3x color(red)((-1))< 10 color(red)((-1))$

this gives us
$- 6 > - 3 x > 9$ $color(green)(-6) > color(green)(-3x) > color(green)(9)$

Now divide both sides by -3

$2 < x < - 3 x$ $color(green)(2) < color(green)(x) < color(green)(-3x)$

There you go!

Answer 2 · 2017-09-21T18:32:41

$2 > x > - 3$ $2 > x > -3$ which can also be written as $- 3 < x < 2$ $-3 < x < 2$

Given: $- 5 < 1 - 3 x < 10$ $-5 < 1-3x < 10$

Subtract 1 from all 3:

$- 6 < - 3 x < 9$ $-6 < -3x < 9$

Divide all 3 by -3:

$2 > x > - 3$ $2 > x > -3$