Question #a9a04

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Question #a9a04

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Answer 1 · 2017-09-16T19:29:53

$- x^{6} + x^{3} + 8$ $-x^6+x^3+8$

Explanation:

Original Problem
${(2 + x - x^{2})}^{3}$ $(2+x-x^2)^3$
Distribute the cube power to all terms inside the parentheses.
$(2^{3} + x^{3} - {(x^{2})}^{3})$ $(2^3+x^3-(x^2)^3)$
Simplify. Remember that the Power of a Power Rule states that a power to a power is multiplied (in this case, $2 \cdot 3$ $2*3$ ).
$(8 + x^{3} - x^{6})$ $(8+x^3-x^6)$
Rearrange terms in descending order
$(- x^{6} + x^{3} + 8)$ $(-x^6+x^3+8)$

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Question #a9a04

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