Question #9c35b

1 Answer
Deepak Pandey
Sep 16, 2017

#lim x rarr ootan^-1 (x)pi/2=pi^2/4#

Explanation:

#lim x rarr ootan^-1 (x)pi/2#
We know that as #x rarr pi/2, tanx rarr oo#
Hence when #x rarr oo, tan^-1x # must approach #pi/2#
#:.lim x rarr ootan^-1 (x)pi/2=pi/2×pi/2=pi^2/4#

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