How do you solve $5y + 9- 2( - 4y - 2) = 5( y - 1)$ ?

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Answer 1 · 2017-09-16T08:35:31

$y=-18/8$

$5y + 9 - 2(-4y-2) = 5(y-1)$

To simplify the eqaution,we need to solve the brackets,we need to multiply $-2$ with $(-4y-2)$ and also $5$ with $(y-1)$

Now, $-2*(-4y-2)$ = $(-2)$ $(-4y)$ + $(-2)(-2)$
Therefore, $-2$ $(-4y-2)$ = $8y +4$

Also, $5*(y-1)$ = $(5*y)-5*(1)$
Therefore, $5.(y-1)$ = $5y-5$

Substituting these values of brackets in equation,we have

$5y+9+8y+4=5y-5$
Therefore, $(5y+8y)+(9+4)=5y-5$
Therefore, $13y +13=5y-5$
Therefore, $(13y-5y)=(-5-13)$
Therefore, $8y=-18$
Thus, $y=-18/8$

How do you solve 5y + 9- 2( - 4y - 2) = 5( y - 1)5y + 9- 2( - 4y - 2) = 5( y - 1)?