How do you evaluate $\frac{20 - (4^{2} \div (2 + 14)) + 5}{4^{2} - 13}$ $(20 - (4^2 \div (2+14)) +5)/(4^2 -13)$ ?

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How do you evaluate $\frac{20 - (4^{2} \div (2 + 14)) + 5}{4^{2} - 13}$ $(20 - (4^2 \div (2+14)) +5)/(4^2 -13)$ ?

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Answer 1 · 2017-09-13T08:49:31

8

Explanation:

$\frac{(20 - (\frac{4^{2}}{(2 + 14)}) + 5)}{(4^{2} - 13)}$ $((20-(4^2/((2+14))) + 5))/((4^2-13))$

To solve this question, we will have to follow the order of operation rule, which states which operations we go through when solving:

The order is:
1. Grouping (....)
2.Exponents
3.Multiplication/division
4.Addition/subtraction

Back to our equation:
we can start by working in the denominator, and in the middle term of the numerator:
$\frac{(20 - \frac{4^{2}}{(2 + 14)} + 5)}{(4^{2} - 13)}$ $((20-color(blue)(4^2/((2+14))) + 5))/color(red)((4^2-13))$

In denominator:
$4^{2} - 13 = 16 - 13 = 3$ $4^2-13=16-13=color(red)(3)$

In numerator:
$\frac{4^{2}}{2 + 14} = \frac{16}{16} = 1$ $4^2/(2+14)=16/16=color(blue)(1)$

Putting values in equation:
$\frac{(20 - 1 + 5)}{3}$ $((20-color(blue)(1)+ 5))/color(red)(3)$

Calculating numerator:
$20 - 1 + 5 = 19 + 5 = 24$ $20-1+5=19+5=24$
$\to \frac{24}{3} = 8$ $rarr 24/3=8$

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How do you evaluate $\frac{20 - (4^{2} \div (2 + 14)) + 5}{4^{2} - 13}$ $(20 - (4^2 \div (2+14)) +5)/(4^2 -13)$ ?

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Explanation:

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