How do you solve $6( w - 3) - 2= - 4( - 2w + 1) - 8w$ ?

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Answer 1 · 2017-09-12T21:26:11

$w=8/3$ or, in decimal form: $w=2.66666 . . .$

First, apply the distributive property to both sides of the equation:

$6(w-3)-2=-4(-2w+1)-8w$

$6w-18-2=8w-4-8w$

Next, on the left side, add $-18$ and $-2$ to the right, to isolate for $w$

$6w=8w-4-8w+20$

On the right side, the $-8w$ and $8w$ terms cancel out, leaving us with:

$6w=-4+20$

$6w=16$

After dividing both side by $6$ :

$w=16/6$

Simplifying the fraction:

$w=8/3$

You can also write the answer in decimal form as:

$2.66666 . . .$

(Where the $6$ repeats forever)

How do you solve 6( w - 3) - 2= - 4( - 2w + 1) - 8w6( w - 3) - 2= - 4( - 2w + 1) - 8w?