Question #0cda4

1 Answer
Sep 11, 2017

#3(n+3)-2n#
simplified version :
#n+9#

Explanation:

let us start by breaking up the given
expression of :
difference..A of 3* the number ..B after it was increased by 3..C.

We see that the number was first increased by 3
#rarr (n)+3#

Then the result was multiplied by 3 (3 times):
#rarr 3((n)+3)#

Then eventually the difference is wanted to be found between the result and twice the number:
#rarr 3((n)+3)-2(n)#

Now simplifying the final expression:
#rarr 3((n)+3)-2(n)=3(n)+9-2n=3n-2n+9=n+9#