How do you solve the system of equations -2x + 2y = - 122x+2y=12 and - 2x - 3y = 132x3y=13?

1 Answer

x=31,y=25x=31,y=25

Explanation:

Let -2x+2y=-122x+2y=12 be equation 1 and -2x-3y=132x3y=13 equation 2.

Subtract equation 2 from equation 1
-2x+2y=-12 (-)-2x-3y=132x+2y=12()2x3y=13
-y=-25y=25
y=25y=25

Substitute y=25y=25 into equation 1 to find the value of xx
-2x+2(25)=-122x+2(25)=12
-2x+50=-122x+50=12
-2x=-622x=62
x=31x=31