How do you solve the system of equations -2x + 2y = - 12−2x+2y=−12 and - 2x - 3y = 13−2x−3y=13?

1 Answer
Loweena Gonasegaran
Sep 1, 2017

x=31,y=25x=31,y=25

Explanation:

Let -2x+2y=-12−2x+2y=−12 be equation 1 and -2x-3y=13−2x−3y=13 equation 2.

Subtract equation 2 from equation 1
-2x+2y=-12 (-)-2x-3y=13−2x+2y=−12(−)−2x−3y=13
-y=-25−y=−25
y=25y=25

Substitute y=25y=25 into equation 1 to find the value of xx
-2x+2(25)=-12−2x+2(25)=−12
-2x+50=-12−2x+50=−12
-2x=-62−2x=−62
x=31x=31

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