How do you solve the system of equations #-2x + 2y = - 12# and #- 2x - 3y = 13#?

1 Answer
Loweena Gonasegaran
Sep 1, 2017

#x=31,y=25#

Explanation:

Let #-2x+2y=-12# be equation 1 and #-2x-3y=13# equation 2.

Subtract equation 2 from equation 1
# -2x+2y=-12 (-)-2x-3y=13#
#-y=-25#
#y=25#

Substitute #y=25# into equation 1 to find the value of #x#
#-2x+2(25)=-12#
#-2x+50=-12#
#-2x=-62#
#x=31#

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