How do you solve the system of equations $- 2 x + 2 y = - 12$ $-2x + 2y = - 12$ and $- 2 x - 3 y = 13$ $- 2x - 3y = 13$ ?

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How do you solve the system of equations $- 2 x + 2 y = - 12$ $-2x + 2y = - 12$ and $- 2 x - 3 y = 13$ $- 2x - 3y = 13$ ?

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Answer 1 · 2017-09-01T09:22:27

$x = 31, y = 25$ $x=31,y=25$

Explanation:

Let $- 2 x + 2 y = - 12$ $-2x+2y=-12$ be equation 1 and $- 2 x - 3 y = 13$ $-2x-3y=13$ equation 2.

Subtract equation 2 from equation 1
$- 2 x + 2 y = - 12 (-) - 2 x - 3 y = 13$ $-2x+2y=-12 (-)-2x-3y=13$
$- y = - 25$ $-y=-25$
$y = 25$ $y=25$

Substitute $y = 25$ $y=25$ into equation 1 to find the value of $x$ $x$
$- 2 x + 2 (25) = - 12$ $-2x+2(25)=-12$
$- 2 x + 50 = - 12$ $-2x+50=-12$
$- 2 x = - 62$ $-2x=-62$
$x = 31$ $x=31$

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How do you solve the system of equations $- 2 x + 2 y = - 12$ $-2x + 2y = - 12$ and $- 2 x - 3 y = 13$ $- 2x - 3y = 13$ ?

1 Answer

Explanation:

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Impact of this question

Science

Math

Humanities

... and beyond

How do you solve the system of equations −2x+2y=−12-2x + 2y = - 12 and −2x−3y=13- 2x - 3y = 13?

1 Answer

Explanation:

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Impact of this question

How do you solve the system of equations $- 2 x + 2 y = - 12$ $-2x + 2y = - 12$ and $- 2 x - 3 y = 13$ $- 2x - 3y = 13$ ?