Question #082ad

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Answer 1 · 2017-08-31T04:06:12

#x=9e^2+3#

Condense the logarithms using the rules:

Then

#ln(x-3)-2ln(3)=2#

#ln(x-3)-ln(3^2)=2#

#ln((x-3)/3^2)=2#

Rewrite by exponentiating both sides with base #e# (that is, undo the logarithm):

#(x-3)/9=e^2#

From here, solving for #x# is simple:

#x=9e^2+3#