What is the standard form of y=(2x+14)(x+12)(7x7)2?

2 Answers

y=47x2+136x+119

Explanation:

y=(2x+14)(x+12)(7x7)2

y=2x2+24x+14x+168(49x298x+49)

y=2x2+24x+14x+16849x2+98x49

y=47x2+136x+119

Aug 30, 2017

y=47x2+136x+119

Explanation:

The equation of a quadratic in standard form is: y=ax2+bx+c

So, this question is asking us to find a,b,c

y=(2x+14)(x+12)(7x7)2

It is probably simplier to break y in its two parts first.

y=y1y2

Where: y1=(2x+14)(x+12) and y2=(7x7)2

Now, expand y1

y1=2x2+24x+14x+168

=2x2+38x+168

Now, expand y2

y2=(7x7)2=72(x1)2

=49(x22x+1)

=49x298x+49

We can now simply combine y1y2 to form y

Thus, y=2x2+38x+168(49x298x+49)

=2x2+38x+16849x2+98x49

Combine coefficients of like terms.

y=(249)x2+(38+98)x+(16849)

y=47x2+136x+119 (Is our quadratic in standard form)

a=47,b=+136,c=+119