Question #4b2cd

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Question #4b2cd

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Answer 1 · 2017-08-25T15:08:54

$108$ $108$

Explanation:

Long method:

Let the first number be $x$ $x$ . We know that, consecutive odd numbers have difference of $2$ $2$

So, the numbers are

$x, x + 2, x + 4, x + 6, x + 8, x + 10, x + 12, x + 14, x + 16$ $color(blue)(x,x+2,x+4,x+6,x+8,x+10,x+12,x+14,x+16$

It is stated that the third term ( $x + 4$ $x+4$ ) is equal to $9$ $9$

$\to x + 4 = 9$ $rarrx+4=9$

$\to x = 9 - 4 = 5$ $color(blue)(rarrx=9-4=5$

So, insert the value of $x$ $x$ in the sequence to get the sum

$\to (5) + (5 + 2) + (5 + 4) + (5 + 6) + (5 + 8) + (5 + 8) + (5 + 10) + (5 + 12) + (5 + 14) + (5 + 16)$ $rarr(5)+(5+2)+(5+4)+(5+6)+(5+8)+(5+8)+(5+10)+(5+12)+(5+14)+(5+16)$

$\to 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21$ $rarr5+7+9+11+13+15+17+19+21$

$\Rightarrow 108$ $color(green)(rArr108$

Hope this helps!!!

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