Question #4b2cd

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Answer 1 · 2017-08-25T15:08:54

#108#

Long method:

Let the first number be #x#. We know that, consecutive odd numbers have difference of #2#

So, the numbers are

#color(blue)(x,x+2,x+4,x+6,x+8,x+10,x+12,x+14,x+16#

It is stated that the third term (#x+4#) is equal to #9#

#rarrx+4=9#

#color(blue)(rarrx=9-4=5#

So, insert the value of #x# in the sequence to get the sum

#rarr(5)+(5+2)+(5+4)+(5+6)+(5+8)+(5+8)+(5+10)+(5+12)+(5+14)+(5+16)#

#rarr5+7+9+11+13+15+17+19+21#

#color(green)(rArr108#

Hope this helps!!!