How do you multiply #(- 3u ^ { 3} v ) ^ { 2}#?

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Answer 1 · 2017-08-24T20:58:35

#9u^6v^2#

First do #-3^2 = 9#

Here you multiply the indices by the indice outside the bracket:

#(u^3)^2 = u^6#

Same goes for the #v#:

#(v^1)^2 = v^2#

Now put the all the parts together to give you an answer of:

#9u^6v^2#