Question #80447

Question

754 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-08-24T00:36:21

$( - e^(lnx) x^3 e^(1-x) )^2 = x^8 e^(2-2x)$

$( - e^(lnx) x^3 e^(1-x) )^2$

First simplify what is inside the parentheses, note that $e^lnx=x$

$= ( -x*x^3*e^(1-x) )^2$

$= ( -x^4e^(1-x) )^2$

Distribute the exponent among what is inside the base of the exponent:
$= (-1)^2 * (x^4)^2 * (e^(1-x))^2$

Simplify:

$= x^8 e^(2-2x)$