What is the range of #f(x)=x^2-5# for the domain #{-3, 0, 5}#?

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Answer 1 · 2017-08-23T22:42:03

See a solution process below:

To find the range we need to solve the function for each value in the domain:

For x = -3:

#f(-3) = -3^2 - 5 = 9 - 5 = 4#

For x = 0:

#f(-3) = 0^2 - 5 = 0 - 5 = -5#

For x = 5:

#f(-3) = 5^2 - 5 = 25 - 5 = 20#

Therefore the range is: {4, -5, 20}