How do you solve the system of equations $-2x + 3y = 3$ and $5x - 6y = - 3$ ?

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Answer 1 · 2017-08-22T06:19:29

Multiply one of the equation so that you can rule out either the $x$ or the $y$ value, then add them up to actually let one of them vanish.

Multiply the first equation by $2$ , then add both equations up.

This gives: $-4x=6y=6$
Adding up: $1x-0y=3$ , simplified: $x=3$ since $0 times y =0$

How do you solve the system of equations -2x + 3y = 3-2x + 3y = 3 and 5x - 6y = - 35x - 6y = - 3?