Question #2976c
1 Answer
Aug 19, 2017
0.573g of silver chloride will be obtained.
Explanation:
Equation:
As HCl is being added in excess,
Amount of
= 0.004002966 mol
Amount of AgCl obtained = 0.004002966 mol
Mass of AgCl obtained = 0.004002966 mol x (107.87 + 35.45) = 0.573705216 g = 0.573g (3 s.f.)
