Question #32f0e

Question

893 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-08-19T01:32:17

#x=0#

Let's simplify the radicals.

#\sqrt(60)=\sqrt(2^2*15)=2\sqrt(15)#

#\sqrt(15)=\sqrt(15)#

#\sqrt(135)=\sqrt(3^2*15)=3\sqrt(15)#

Now, we know that if two radicals have the same value underneath the square root, we can combine them, like so:

#a\sqrt(b)-csqrt(b)=(a-c)sqrt(b)#

So,

#2\sqrt(15)+sqrt(15)-3sqrt(15)=3sqrt(15)-3sqrt(15)=0#

Thus,

#0=\sqrt(x)# so #x=0#.