How do you solve #\frac { 3} { n } + \frac { 3} { n ^ { 2} - 5n } = \frac { 1} { n ^ { 2} - 5n }#?

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Answer 1 · 2017-08-14T15:09:30

#"Answer :"n=13/3#

#3/n+3/(n^2-5 n)=1/(n^2-5 n)#

#3/n=1/(n^2-5 n)-3/(n^2-5 n)#

#3/n=(-2)/(n^2-5 n)#

#-2 n=3(n^2-5 n)#

#-2 n=3 n^2-15n#

#3n^2-15n+2n=0#

#3 n^2-13n=0#

#3n^2=13n#

#3cancel(n^2)=13cancel(n)#

#3n=13#

#(cancel(3)n)/cancel(3)=(13)/3#

#n=13/3#